Answer:
[tex]\frac{3x-1}{8(x-1)}[/tex]
Step-by-step explanation:
The given expression is
[tex]\frac{\frac{2}{x-1}+\frac{1}{x}}{\frac{8}{x} }[/tex]
The simplified form would be:
[tex]\frac{\frac{2x+x-1}{(x-1)x} }{\frac{8}{x} }\\\frac{\frac{3x-1}{x(x-1)}}{\frac{8}{x}}\\ \frac{x(3x-1)}{8x(x-1)}\\\frac{3x-1}{8(x-1)}[/tex]
To get the simplest form, we first sum the fractions and then divided the two fractions we got.
At the end, we have the result
[tex]\frac{3x-1}{8(x-1)}[/tex]
Where x-1 cannot be eliminated, because the variable have different variables.
