6y6
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What is 4^2y-3^2=-5y+(-5+7)
Please explain step by step i need this asap :/

Respuesta :

y = 11/21

To solve this first evaluate the power (then calculate the sum):

[tex]4^{2}[/tex]y - [tex]3^{2}[/tex] = 5y + (-5 + 7)

16y - 9 = -5y + 2


Next Move terms (move variable to the left side and change its sign) (Move constant to the right side and change its sign):

16y - 9 = -5y + 2

16y + 5y = 2 + 9


Next Collect the like terms and calculate the sum:

16y + 5y = 2 + 9

21y = 11


Lastly divide both sides of the equation by 21:

21y = 11

y = [tex]\frac{11}{21}[/tex]


[tex]4^2y-3^2=-5y+(-5+7)[/tex]

simplify stuff by pemdas, 4^2=16, 3^2=9, -5+7=2

[tex]16y-9=-5y+2[/tex]

add 5y to both sides

[tex]21y-9=2[/tex]

add 9 both sides

[tex]21y=11[/tex]

divide both sides by 21

[tex]y=\frac{11}{21}[/tex]