Respuesta :
Answer:
50% Hh - short, 50% hh - long
Explanation:
The top of the Punnett square would have Hh and the side would have hh. When crossed, the results would be Hh, hh, Hh, and hh. So half of the offspring have short hair and the other half have long hair.
When crossing two h0m0zyg0us individuals, one of them expressing the dominant trait and the other one the recessive trait, the whole progeny will be heter0zyg0us, expressing the dominant trait. GR=100%, PhR= 100%.
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Available data:
- Single diallelic gene coding for hair length
- Short hair is dominant to long hair
- S allele is dominant coding for short hair
- s allele is recessive coding for long hair
Cross: A guinea pig that h0m0zyg0us dominant for hair is crossed with a female who has long hair
- The guinea pig that is h0m0zyg0us dominant ⇒ SS
- The female that has long hair must be h0m0zyg0us recessive ⇒ ss
Parentals) SS x ss
Gametes) S S s s
Punnett square) S S
s Ss Ss
s Ss Ss
F1) 100% heter0zyg0us individuals, Ss, expressing short hair.
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