The grams of copper metal that are produced from the reaction of 21.84 ml of 0.108 M cu2+ is 0.150 grams
calculation
Step 1 : write the equation for reaction
Cu^2+(aq) + Zn(s)→ Cu (s) + Zn^ 2+ (aq)
Step 2: calculate the moles of CU 2+
moles = molarity x volume in liters
molarity = 0.108M= 0.108 mol /l
volume in liters = 21.84 /1000 =0.02184 L
moles is therefore= 0.108 mol/l x 0.02184 L =0.00236 moles
Step 3 use the mole ratio to determine moles of Cu
that is CU 2+ : Cu is 1:1 therefore the moles of CU is also =0.00236 moles
step 4: calculate the mass of CU
Mass = moles x molar mass
from periodic table the molar mass of Cu = 63.5 g /mol
mass= 0.00236 moles x 63.5 g/mol = 0.150 grams
