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A family has two cars. During one particular week, the first car consumed 35 gallons of gas and the second consumed
25 gallons of gas. The two cars drove a combined total of
2150 miles, and the sum of their fuel efficiencies was
70 miles per gallon. What were the fuel efficiencies of each of the cars that week?

Respuesta :

jcherry99

Call car one = o

Call car two = t

o = 35 gallons

t = 25 gallons

d1 = do

d2 = 2150 - do

effici_0 = e

effic_2 = 70 - e

35*e = do

25*(70 - e) = 2150 - do         Substitute do into this equation

25*(70 - e) = 2150 - 35e       Remove the  brackets on the left

1750 - 25e = 2150 - 35e       Add 35e to both sides

1750 - 25e + 35e = 2150 - 35e + 35e

1750 + 10e = 2150                 Subtract 1750 from both sides.

1750 - 1750 + 10e = 2150 - 1750

10e = 400                              Divide by 10

e = 40                                    Answer for Car 1

70 - e = effic2                        

70 - 40 = 30                         Answer for Car 2


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