Use the student's t distribution to find tc for a 0.95 confidence level when the sample is 17. (round your answer to three decimal places.)

Respuesta :

Answer:

The t critical value at 0.05 significance level for [tex]df=n-1=17-1=16[/tex] is:

[tex]t_{critical}=\pm2.120[/tex]

Step-by-step explanation:

We are given confidence level =0.95

[tex]n=17[/tex]

Significance level = 1 - confidence level

                              = 1 - 0.95

                               = 0. 05

Degrees of freedom = n - 1 = 17 - 1 = 16

Therefore, using the t distribution table, the t critical values are:

[tex]t_{critical} = \pm 2.120[/tex]