Answer:
[tex]v_f=9.0774m/s[/tex]
Step-by-step explanation:
Let's assume
initial velocity =vi
final velocity=vf
initial height =hi
final height =hf
acceleration due to gravity =g
we can use formula
[tex]\frac{1}{2}v_i^2+gh_i= \frac{1}{2}v_f^2+gh_f[/tex]
we are given
[tex]v_i=2m/s[/tex]
[tex]h_i=2\times 2=4[/tex]
[tex]h_f=0[/tex]
[tex]g=9.8m/s^2[/tex]
now, we can plug values
[tex]\frac{1}{2}(2)^2+(9.8)(4)= \frac{1}{2}v_f^2+(9.8)(0)[/tex]
now, we can solve for vf
[tex]\frac{1}{2}(2)^2+(9.8)(4)= \frac{1}{2}v_f^2[/tex]
we get
[tex]v_f=9.0774m/s[/tex]
