2x - y = 13 ------------- [1]
3x + y = 12 ------------ [2]
Adding both Equations [1] and [2], We get :
⇒ (2x - y) + (3x + y) = 13 + 12
⇒ 2x + 3x - y + y = 25
⇒ 5x = 25
⇒ x = 5
Substituting x = 5 in Equation [1], We get :
⇒ 2(5) - y = 13
⇒ 10 - y = 13
⇒ y = 10 - 13
⇒ y = -3
⇒ (x , y) = (5 , -3)
Option B is the Answer
B
Given the 2 equations
2x - y = 13 → (1)
3x + y = 12 → (2)
add (1) and (2) term by term to eliminate the term in y
5x = 25 ( divide both sides by 5 )
x = 5
substitute x = 5 in either of the 2 equations and solve for y
(2) : (3 × 5 ) + y = 12
15 + y = 12 ( subtract 15 from both sides )
y = - 3
solution is (5, - 3 ) → B
