A block is released from rest, at a height h, and allowed to slide down an inclined plane. There is friction on the plane. At the bottom of the plane, there is a spring that the block will compress. After compressing the spring, the block will slide up the plane to some maximum height, hA, after which it will again slide back down. How much work is done on the block between its release at height h and its ascent to its next maximum height?

1. More information is needed.
2. 2µ mA g hA
3. mA g (h − hA)
4. 0
5. mA g (h − hA) + 2µ mA g hA
6. None of these

The block is released from a particular height from rest. It means that the block has only the potential energy stored in it. The kinetic energy of the block is zero.

Now as the block comes to the bottom of the plane on the rough incline and compresses the spring, it losses some of the energy and some energy is stored in the spring as spring potential energy.

The spring finally rebounds to some height [tex]{h_A}[/tex] where the block finally comes to rest and then starts to slide back.

During its motion from the starting point to the height [tex]{h_A}[/tex], the kinetic energy of the block remains same at the initial and final position because initially it was at rest and finally at [tex]{h_A}[/tex] it is again at rest.

According to the work energy theorem, the amount of work done on the system is equal to the change in the kinetic energy of the system. Here, the change in kinetic energy of the system is zero. So, the work done on the system will also be zero.

Thus, the work done on the block between its release from height [tex]h[/tex] and its ascent to the height [tex]{h_A}[/tex] will be [tex]\boxed0[/tex].

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Answer Details:

Grade: Senior School

Subject: Physics

Chapter: Work-Energy Theorem

Keywords: Block released from rest, down an inclined plane, compress, a spring, work energy theorem, change in kinetic energy, maximum height.

snehashish65 snehashish65 · Answer 2 · 2021-10-11T15:18:29+02:00

Answer:

The work done on crate between release height and ascent height is zero. Hence, option (4) is correct.

Explanation:

According to the work-energy theorem, "Work done on an object by all the forces is equal to the change in kinetic energy of the object". This gives,

Work done = Change in kinetic energy

[tex]W=KE_{final}-KE_{initial}[/tex] .............................................(1)

Now, when the object is at height h, then it was at rest, so the kinetic energy at height h is zero. [tex](KE_{initial} =0)[/tex].

Similarly, when it re-bounces to height [tex]h_{A}[/tex], again it comes to rest and its kinetic energy becomes zero. [tex](KE_{final} =0)[/tex].

From equation (1),

[tex]W=0-0\\W=0[/tex]

Thus, the work done on crate between release height and ascent height is zero.

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https://brainly.com/question/17056946?referrer=searchResults