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A certain drug is made from only two ingredients: compound A and compound B. There are 8 milliliters of compound A used for every 5 milliliters of compound B. If a chemist wants to make 845 milliliters of the drug, how many milliliters of compound B are needed?

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bunnymarshmarloykw47

Let 8 milliliters of compound A and 5 milliliters of compound B be a mixture.

We can then find how many mixture is needed for 845 milliliters of the drug by dividing it by (8+5=13):

845 ÷ 13

=65

As 65 mixture is used and each mixture include 5 milliliters of compound B, we can find the amount of compound B by multiplying 65 by 5

65 x 5

=325 milliliters

Therefore the answer is 325 milliliters.

Hope it helps!


MrRoyal

The comparison of two compounds (say A and B) implies that compounds are represented as a ratio of the amount of one compound to the other.  The amount of compound B needed for the drug is 325mL.

Given the following ratio

[tex]A : B =8 : 5[/tex]

[tex]Mixture = 845mL[/tex]

To calculate the amount of compound B needed, we make use of the following formula:

[tex]B =\frac{B\ Ratio}{A\ Ratio + B\ Ratio} * Mixture[/tex]

This gives

[tex]B =\frac{5}{8+5} * 845mL[/tex]

[tex]B =\frac{5}{13} * 845mL[/tex]

[tex]B =5*65mL[/tex]

[tex]B =325mL[/tex]

Hence, the amount of compound B needed for the drug is 325mL.

Read more about proportions at:

https://brainly.com/question/21969271

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