Respuesta :
bear in mind that Gravitational capacity potential = mass * height * g. So, a) (i) artwork achieved = substitute in potential = a hundred * 9.80 two * 2 = 1964 J (ii) The sideways movements make no distinction to the terrific artwork achieved. the burden nonetheless finally ends up 2 m from the floor, so the comparable volume of artwork must be achieved. artwork achieved = 1964 J b) whilst the burden is released, its PE is switched over into Kinetic potential. So, on the instantaneous beforehand is hits his toe, we've 1964 = (a million/2) m v^2 v^2 = 1964 / (0.5 * a hundred) = 39.28 v = ?(39.28) = 6.27 m/s
The power input to raise the ball is 1225 watts.
The power input to raise the ball is 1.64 hp.
How do you calculate the power?
Given that a weightlifter raises a barbell of mass 100 kg from the floor to over his head ( 2.5 meters) in 2 seconds.
Hence the potential energy can be calculated as given below.
[tex]PE = mgh[/tex]
[tex]PE = 100 \times 9.8\times 2.5[/tex]
[tex]PE = 2450 \;\rm J[/tex]
The work done in raising the ball will be equivalent to the potential energy. Thus, work done is 2450 Joules. The power can be calculated as given below.
[tex]P = \dfrac {W}{t}[/tex]
Where W is the work done and t is time. Substituting the values, we get the power.
[tex]P = \dfrac {2450}{2}[/tex]
[tex]P = 1225 \;\rm Watts[/tex]
Hence the power input to raise the ball is 1225 watts.
We know that one horsepower is equal to 746 watts. Then,
[tex]746 \;\rm Watts = 1 \;\rm hp\\1225 \;\rm watts = \dfrac {1}{746} \times 1225[/tex]
[tex]1225 \;\rm watts = 1.64 \;\rm hp[/tex]
Hence the power input to raise the ball is 1.64 hp.
To know more about the power, follow the link given below.
https://brainly.com/question/1618040.
