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Consider the following reaction. CS2(g) + 3O2(g) CO2(g) + 2SO2(g) If the volumes of all products and reactants are measured at 75°C and 1 atm, what is the total volume of products if 5.00 L of CS2 and 18.0 L of O2 are used?

Respuesta :

Given reaction:

CS2(g) + 3O2(g) → CO2(g) + 2SO2(g)

Based on the reaction stoichiometry;

1 L of CS2 will react will react with 3 L of O2 to form 1 L of CO2 and 2 L of SO2.

Here, CS2 and O2 combine in the ratio 1:3 to form products of total volume= 1+2 = 3 L

Given volume of CS2 = 5.00 L

volume of O2 = 18.0 L

Based on the reactant stoichiometry: 5 L CS2 will combine with 15 L of O2 to form products with a total volume of 15.0 L

Ans: Product total volume (CO2 + SO2) = 15.0 L

Unreacted O2 = 18.0 - 15.0 = 3.0 L


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