Plz help me get the answer to these

- 9y - 4
factorise the numerator by taking out a common factor of 5y
45y² + 20y = 5y(9y + 4)
The expression now becomes
[tex]\frac{5y(9y+4)}{-5y}[/tex]
the 5y on numerator/ denominator cancel leaving
- (9y + 4) = - 9y - 4 ← quotient
Answer:
Step-by-step explanation:
[tex]\dfrac{45y^2+20y}{-5y}=\dfrac{45y^2}{-5y}+\dfrac{20y}{-5y}=-9y-4[/tex]