Line CD is Passing through the Points (3 , -5) and (6 , 0)
Slope of a Line Passing through two points (x₁ , y₁) and (x₂ , y₂) is given by :
[tex]\heartsuit\;Slope(m) = \frac{y_1 - y_2}{x_1 - x_2}[/tex]
here x₁ = 3 and x₂ = 6 and y₁ = -5 and y₂ = 0
[tex]\heartsuit\;Slope(m) = \frac{-5 - 0}{3 - 6} = \frac{-5}{-3} = \frac{5}{3}[/tex]
We know that the form of line passing through point (x₀ , y₀) and having slope m is : y - y₀ = m(x - x₀)
Here the line passes through the point (3 , -5) and (6 , 0)
We can take any one point of the both
let us take (3 , -5)
x₀ = 3 and y₀ = -5 and we found [tex]m = \frac{5}{3}[/tex]
Equation of the line : [tex]y + 5 = \frac{5}{3}(x - 3)[/tex]
⇒ 3y + 15 = 5x - 15
⇒ 5x - 3y = 30
Option 2 is the Answer
The equation of the line CD expressed in standard form which passes through the points C(3, –5) and D(6, 0) is;. 5x - 3y = 30
The equation of a straight line can be determined by first determining the slope of the line if two points are given on the straight line.
m = 5/3.
The equation of the line can then be gotten from the slope and a pair of ordinates as follows;
5x - 3y = 30.
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