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I've been trying to solve this for a while, but I don't understand. I'd really appreciate some help with it.

2. The formula M = log I/S determines the magnitude of an earthquake, where I is the intensity of the earthquake and S is the intensity of a “standard earthquake.” How many times stronger is an earthquake with a magnitude of 8 than an earthquake with a magnitude of 6? Show your work.

Respuesta :

it should be
[tex] log_{6}(8) [/tex]
which is 1.16.....

tramserran

Answer: 100

Explanation:

formula: log ([tex]\frac{Intensity}{Standard}[/tex]) = Magnitude

log ([tex]\frac{Intensity}{Standard}[/tex]) = 8                 log ([tex]\frac{Intensity}{Standard}[/tex]) = 6

      [tex]\frac{Intensity}{Standard}[/tex] = 10⁸                    [tex]\frac{Intensity}{Standard}[/tex] = 10⁶

Intensity = 10⁸ * Standard          Intensity = 10⁶ * Standard

Comparing the intensity of the Magnitude 8 to Magnitude 6:

[tex]\frac{10^{8}*Standard}{10^{6}*Standard} = 10^{2}[/tex]

A magnitude 8 earthquake is 100 times stronger than a magnitude 6 earthquake


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