Answer:
One.
Step-by-step explanation:
You can find discontinuities by observing the domain.
Observe that the domain is
[tex](x<-2)U(-2<x\leq 4)U(4<x<6)U(x\geq 6)[/tex]
You can observe that the only interval limit that is not included is [tex]x=-2[/tex], that represents a discontinuation, because the function is not defined for that element of the domain.
Remember that discontinuities refers to restrictions in the domain, that is, all values that are not included in the domain set, like in this case, [tex]x=-2[/tex] is not included, so it represents a discontinuation of the piecewise function.
Therefore, there's one discontinuity.
