13.) To solve this problem, simply use the equation for finding the distance between 2 points.
[tex]AB: 5[/tex]
[tex]BC: \sqrt{(4-0)^2+(5-2)^2}= \sqrt{16+9}=5[/tex]
If we use this method for CD and EF, we can see that they are also 5 units apart from each other.
[tex]FA: 3[/tex]
So, the sum of your lengths is 26 yards.
14.) The answer is A. Since measurements can never be negative, this eliminates option B.
15.) Once again find the distance between two points. In this case, it's [tex]\sqrt{(5-1)^2+(0-0)^2}[/tex] which simplifies into [tex]\sqrt{16}[/tex] which is 4. Because there are 4 fours, the answer is 16 inches. Know that it is not 16 square inches because this is perimeter we're talking about; not area.
16.) The formula for the volume of this cylinder is [tex]3.14(5^2)(15)[/tex], which is 1177.5 cubic centimeters. [tex]\frac{4500}{1177.5} = 3.82...[/tex], but since it is asking for whole candles, this means you can make 3 and have 0.8 cubic centimeters left.
17. Let's start with what we know:
- Radius of cone is 1.625 inches
- Height of cone is 4.5 inches
- Diameter of the gumball is 4.5 inches
Note: Volume of the gumball will be represented by Vg, volume of the cone by Vc, approximate volume of flavored ice by V, and pi by 3.14.
- Volume of a sphere = [tex]\frac{4(3.14)r^3}{3}[/tex]
Volume of the gumball: [tex]Vg = \frac{12.56*1^3}{3}[/tex] = [tex]4.186667in^3[/tex]
- Volume of the cone: [tex]Vc=3.14(1.625^2)(4.5) = 37.312031[/tex]
- Approximate volume of flavored ice: [tex]V=Vc-Vg = 33.125364[/tex]
- Volume rounded to nearest tenth: 33.1 cubic inches.
Hope this was helpful.
