[tex]\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{1})~\hspace{10em} slope = m\implies -6 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-1=-6(x-3) \\\\\\ y-1=-6x+18\implies y=-6x+19[/tex]
bearing in mind that
standard form for a linear equation means
• all coefficients must be integers, no fractions
• only the constant on the right-hand-side
• all variables on the left-hand-side, sorted
• "x" must not have a negative coefficient
then we'd end up with 6x + y = 19.
Answer:
6x + y = 19
Explanation:
The point-slope formula for a straight line is
y – y₁ = m(x – x₁)
x₁ = 3; y₁ = 1; m = -6 Substitute the values
y – 1 = -6(x-3) Remove parentheses
y – 1 = -6x + 18 Add 1 to each side
y = -6x + 19 Add 6x to each side
6x + y = 19
The graph is a straight line with a y-intercept at y = 19 and
slope = -18/3 = -6.
