Answer: There are [tex]3.67\times 10^{21} [/tex] number of nicotine molecules in 1 gram of nicotine.
Explanation:
NIcotine is an organic compound with chemical formula of [tex]C_{10}H_{14}N_2[/tex]
Given mass of nicotine = 1.00 g
Molecular mass of Nicotine = 162.23 g/mol
[tex]\text{moles of compound}=\frac{\text{given mass of compound}}{\text{molar mass of compound}}=\frac{1.00 g}{162.23 g/mol}=0.0061 mol[/tex]
Number of molecules of compound:
[tex]\text{moles of compound}\times {Avogadro number}=0.0061 mol\times 6.022\time 10^{23}=3.67\times 10^{21} molecules[/tex]
There are [tex]3.67\times 10^{21} molecules[/tex] in 1 gram of nicotine.