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If cos theta =0.3090, which of the following represents approximate values of sin theta for 0 degrees <90 degrees?

Respuesta :

[tex]sin\theta=\sqrt{1-0.3090^2}=\sqrt{1-0.095481}=\sqrt{0.904519}\approx0.9511[/tex]

Answer:

B........................................................

Step-by-step explanation:

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