The table below shows the temperature in degrees for eight consecutive days as well as the respective number of ice cream cones an ice cream shop sold on each of these days.


Temperature: 68 77 83 85 89 94 96 99

Number of cones: 403 447 457 465 489 503 543 576


about how many ice cream cones would you expect the shop to sell if the temperature one day is 106 degrees?

Respuesta :

Solution:

Representing the points on scatter plot

We will first find the line of best fit using the method of least square.

Line of best fit is the line inside the scatter plot which shows about equal number of points above or below  the line.

Mean of X values =A=[tex]\frac{68+77+83+85+89+94+96+99}{6}=\frac{697}{8}=87.125[/tex]

Mean of Y values = B=[tex]\frac{403 +447 +457 +465 +489 +503 +543 +576}{8}=\frac{3883}{8}=485.375[/tex]

X values - Mean=X-A= -19.125, -10.125, -4.125, -2.125, 1.875, 6.875, 8.875, 11.875

Y Values - Mean = Y - B= -82.375,-38.375, -28.375,-20.375, 3.625,17.625,57.875,90.875

Slope= m=[tex]\frac{Sum(X-A)(Y-B)}{Sum(X-A)^2}=\frac{3839.868}{760.3748}=5.0499[/tex]

Y intercept

C=B- m A

 =485.375 - (5.0499)×(87.125)

 = 485.375- 439.9784

=   45.3966

The equation of best fit of line is , Y = m X + C i.e

y=5.05 x + 45.40 (Taking approx value of m and c)

When temperature is 106 degrees, then

Number of cones= 5.05×106 + 45.40

                             = 535.30 +45.40

                              =   580.70

                           =581(Round figure)


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