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kenmyna

   The volume  at standard  pressure  is 162.5 L

  calculation

The  volume  at Standard pressure (760  mm hg)  is calculated using the Boyle's  law formula

That is P₁V₁ =P₂V₂

where;

P₁=650 mmHg

V₁= 190 L

P₂ = 760 mm hg

V₂ =? L

make   V₂   the formula of the subject  by diving  both side of equation by P₂

V₂  is therefore = P₁V₁/P₂

= {(650 mmHg x 190 L) / 760 mmHg} =162.5 L

Answer : The volume of the gas at standard pressure (1 atm) is, 162.45 L

Solution : Given,

Initial pressure of gas = 650 mmHg = [tex]\frac{650}{760}=0.855atm[/tex]    [tex](1atm=760mmHg)[/tex]

Initial volume of gas = 190 L

Final pressure of gas = 1 atm     (standard pressure is 1 atm)

Formula used : [tex]\frac{P_1}{P_2}=\frac{V_2}{V_1}[/tex]

where,

[tex]P_1[/tex] = initial pressure of gas

[tex]P_2[/tex] = final pressure of gas

[tex]V_1[/tex] = initial volume of gas

[tex]V_2[/tex] = final volume of gas

Now put all the given values in the above formula, we get

[tex]\frac{0.855atm}{1atm}=\frac{V_2}{190L}[/tex]

By rearranging the terms, we get the final volume of the gas.

[tex]V_2=162.45L[/tex]

Therefore, the volume of the gas at standard pressure (1 atm) is, 162.45 L

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