7x ( x + 1.8 ) = 0 → x = 0 or x = -1.8
Discriminant of quadratic equation ( ax² + bx + c = 0 ) could be calculated by using :
From the value of Discriminant , we know how many solutions the equation has by condition :
D < 0 → No Real Roots
D = 0 → One Real Root
D > 0 → Two Real Roots
Let us now tackle the problem!
Given :
[tex]7x ( x + 1.8 ) = 0[/tex]
Solution :
[tex](7x )( x + 1.8 ) = 0[/tex]
[tex](7x) = 0 \texttt{ or } (x + 1.8) = 0[/tex]
[tex]x = 0 \div 7 \texttt{ or } x = 0 - 1.8[/tex]
[tex]x = 0 \texttt{ or } x = - 1.8[/tex]
Grade: High School
Subject: Mathematics
Chapter: Quadratic Equations
Keywords: Quadratic , Equation , Discriminant , Real , Number , Solution , Zero , Root
The value of x are [tex]\boxed{x = 0}[/tex] and [tex]\boxed{x = 1.8}.[/tex]
Further explanation:
Given:
The equation is [tex]7x\left( {x + 1.8} \right).[/tex]
Explanation:
Degree is defined as the highest power of the polynomial function.
The Fundamental Theorem of Algebra states that the polynomial has n roots if the degree of the polynomial is n.
[tex]f\left( x \right) = a{x^n} + b{x^{n - 1}} + \ldots + cx + d[/tex]
The polynomial function has n roots or zeroes.
The given equation is [tex]7x\left( {x + 1.8} \right).[/tex]
Solve the equation [tex]7x\left( {x + 1.8} \right)[/tex] to obtain the value of [tex]x[/tex].
[tex]\begin{aligned}7x\left( {x + 1.8} \right)&= 0\\7x &= 0{\text{ or }}x + 1.8 &= 0\\x&= 0{\text{ or }\;}x &= - 1.8\\\end{aligned}[/tex]
The value of [tex]x[/tex] are [tex]\boxed{x = 0}[/tex] and [tex]\boxed{x = 1.8}.[/tex]
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Answer details:
Grade: High School
Subject: Mathematics
Chapter: Polynomial
Keywords: power function, 7x(x+1.8), degree, represented, table, degree of the polynomial, roots, linear equation, quadratic equation, zeros, function, polynomial, solution, cubic function, degree of the function.
