Diagonal AC divides the trapezoid ABCD (with bases AD and BC , AD>BC) into two similar triangles, △ABC and △DCA. Find AC if BC=4 cm and AD=9 cm.

Respuesta :

Answer:

AC= 6 cm

Step-by-step explanation:

It is given that ABCD is a trapezoid

Also AC divides the trapezoid into two similar triangles

ΔABC≈ΔDCA

The ratio of corresponding sides of similar triangles are equal, so we have

[tex]\frac{AB}{CD} =\frac{BC}{AC} =\frac{AC}{AD}[/tex]

now we can take

[tex]\frac{BC}{AC} =\frac{AC}{AD}[/tex]

[tex]\frac{4}{AC} =\frac{AC}{9}[/tex]     ( since BC=4 and AD= 9)

now we cross multiply

[tex]4(9)=AC^{2}[/tex]

[tex]AC^{2}=36[/tex]

[tex]AC=\sqrt{36}[/tex]    (taking square root )

AC= 6 cm