Respuesta :
Answer:
B
Step-by-step explanation:
given the first 3 terms of the geometric sequence - 4, 20, - 100
with r = [tex]\frac{-100}{20}[/tex] = [tex]\frac{20}{-4}[/tex] = - 5
the n th term formula ( explicit formula ) is
[tex]a_{n}[/tex] = [tex]a_{1}[/tex] [tex]r^{n-1}[/tex]
here r = - 5 and [tex]a_{1}[/tex] = - 4, hence
[tex]a_{n}[/tex] = - 4 [tex](-5)^{n-1}[/tex] with n ≥ 1
This question is solved using geometric sequence concepts, and doing this, we get that the correct option is:
[tex]a_n = -4(-5)^{n-1}, n \geq 1[/tex], second option
Geometric sequence:
In a geometric sequence, the quotient between consecutive terms is the same, called common ration, and the general equation is given by:
[tex]a_n = a_1q^{n-1}, n \geq 1[/tex]
In which [tex]a_1[/tex] is the first term and q is the common ratio.
-------------------------------------------------------
n an
1 −4
2 20
3 −100
First term is -4, so [tex]a_1 = -4[/tex], then:
[tex]a_n = a_1q^{n-1}, n \geq 1[/tex]
[tex]a_n = -4q^{n-1}, n \geq 1[/tex]
The common ratio is:
[tex]q = \frac{-100}{20} = \frac{20}{-4} = -5[/tex]
Thus:
[tex]a_n = -4(-5)^{n-1}, n \geq 1[/tex] is the sequence.
A similar example is given at https://brainly.com/question/24078619