Answer:
The height of the cliff is 31.17 feet.
Step-by-step explanation:
For better understanding of the solution see the attached figure :
Let the height of cliff be x feet.
In ΔABC and ΔDEC,
m∠ABC = m∠DEC = 90° (Angle made between the height and the ground is right angle)
∠ACB = ∠DCE ( Angle of reflection = Angle of incidence because N is normal )
So, By AA postulate of similarity of triangles, ΔABC ~ ΔDEC
Now as triangles are similar, their sides will be proportional to each other.
[tex]\frac{AB}{DE}=\frac{BC}{EC}=\frac{AC}{DC}\\\\Taking,\frac{AB}{DE}=\frac{BC}{EC}\\\\\implies \frac{5.5}{x}=\frac{6}{34}\\\\\implies x=\frac{34\times 5.5}{6}\\\\\bf\implies x = 31.17[/tex]
Hence, The height of the cliff is 31.17 feet
Answer:
Step-by-step explanation:
5.5(34)
187
31.2
=
cliff’s dist. to the mirror
cliff’s height
=
34
h
=6h
=6h
≈h
31.2
