Answer : The excess of electrons on the penny are, [tex]2.5\times 10^{10}[/tex] electrons
Solution : Given,
Total charge = [tex]-4.0\times 10^{-9}C[/tex]
Charge on electron = [tex]-1.6\times 10^{-19}C[/tex]
Formula used :
[tex]\text{Excess of electrons}=\frac{\text{Total charge}}{\text{Charge of electron}}[/tex]
Now put all the given values in this formula, we get the excess of electrons present on the penny.
[tex]\text{Excess of electrons}=\frac{\text{Total charge}}{\text{Charge of electron}}=\frac{-4.0\times 10^{-9}C}{-1.6\times 10^{-19}C/e^-}=2.5\times 10^{10}e^-[/tex]
Therefore, the excess of electrons on the penny are, [tex]2.5\times 10^{10}[/tex] electrons
