contestada

When a point charge of +q is placed on one corner of a square, an electric field strength of 2 N/C is observed at the center of the square. Suppose three identical charges of +q are placed on the remaining three corners of the square. What is the magnitude of the net electric field at the center of the square?a. The magnitude of the net electric field at the center of the square is 6 N/C.b. The magnitude of the net electric field at the center of the square is 0 N/C.c. The magnitude of the net electric field at the center of the square is 4 N/C.d. The magnitude of the net electric field at the center of the square is 8 N/C.e. The magnitude of the net electric field at the center of the square is 2 N/C.

Respuesta :

johanrusli

The magnitude of the net electric field at the center of the square is 0 N/C

[tex]\texttt{ }[/tex]

Further explanation

Electric charge consists of two types i.e. positively electric charge and negatively electric charge.

[tex]\texttt{ }[/tex]

There was a famous scientist who investigated about this charges. His name is Coulomb and succeeded in formulating the force of attraction or repulsion between two charges i.e. :

[tex]\boxed {F = k \frac{Q_1Q_2}{R^2} }[/tex]

[tex]\boxed {E = F \div q = k \frac{Q}{R^2} }[/tex]

F = electric force (N)

E = electric field strength (N/C)

k = electric constant (N m² / C²)

q = electric charge (C)

r = distance between charges (m)

The value of k in a vacuum = 9 x 10⁹ (N m² / C²)

Let's tackle the problem now !

[tex]\texttt{ }[/tex]

Given:

electric field strength of a point charge = 2 N/C

point charge = +q C

Asked:

magnitude of the net electric field = E = ?

Solution:

Let's illustrate this problem as shown in the attachment.

Each of the identical charges will produce electric field strength of 2 N/C at the center of the square.

[tex]]\boxed{E_1 = E_2 = E_3 = E_4 = 2 N/C}[/tex]

[tex]\texttt{ }[/tex]

The direction of the electric field strength of each of the point charges is such that it will cancel each other out. Therefore the magnitude of the net electric field at the center of the square is 0 N/C.

[tex]\texttt{ }[/tex]

Learn more

  • The three resistors : https://brainly.com/question/9503202
  • A series circuit : https://brainly.com/question/1518810
  • Compare and contrast a series and parallel circuit : https://brainly.com/question/539204

[tex]\texttt{ }[/tex]

Answer details

Grade: High School

Subject: Physics

Chapter: Static Electricity

Ver imagen johanrusli
onyebuchinnaji

The magnitude of the net electric field at the center of the square is 0 N/C.

The given parameters;

  • magnitude of the electric field strength, E = 2 N/C
  • magnitude of the charges, = +q

The magnitude of each positive charge is determined by applying Coulomb's law as shown below;

[tex]E = \frac{F}{q} = \frac{kq}{r^2}[/tex]

where;

  • r is the equidistance of each charge from the corners of the square

The distance from the corners of the square to the center is the same and the electric field of two opposite charges will cancel out because they will be acting in opposite direction.

[tex]E_1 = E_2 = E_3 = E_4 = 2\ N/C\\\\E_1 - E_4 = 0 \ \ and \ \ E_2 - E_3 = 0\\\\\E_{net} = 0[/tex]

Thus, the magnitude of the net electric field at the center of the square is 0 N/C.

Learn more here:https://brainly.com/question/20317254

Otras preguntas