contestada

The first three steps in writing f(x) = 40x + 5x2 in vertex form are shown. Write the function in standard form. f(x) = 5x2 + 40x Factor a out of the first two terms. f(x) = 5(x2 + 8x) Form a perfect square trinomial. = 16 f(x) = 5(x2 + 8x + 16) – 5(16) What is the function written in vertex form? f(x) = 5(x + 4) – 80 f(x) = 5(x + 8) – 80 f(x) = 5(x + 4)2 – 80 f(x) = 5(x + 8)2 – 80

Respuesta :

Jasten

Answer:

Rewrite f(x) = 40x + 5x2 as   f(x) = 5x^2 + 40x

Factor out the 5:  f(x) = 5(x^2 + 8x)

Complete the square:  f(x) = 5(x^2 + 8x + 16 - 16) = 5(x+4)^2 - 80 (answer)

Step-by-step explanation:


abidemiokin

The  first three steps are

  • Write the function in standard form
  • Factor out the coefficient of x^2 from the expression
  • Complete the square in parenthesis by forming a perfect square.

Given the function

  • f(x) = 40x + 5x^2

This can be rewritten as:

f(x) = 5x^2 + 40x

To write in vertex form, we will follow the steps:

Step 1; Factor out the coefficient of x^2 from the expression to hav:

f(x) = 5(x^2+8x)

Step 2: Complete the square in parenthesis by forming a perfect square.

f(x) = 5(x^2+8x + (8/2)^2) - (8/2)^2

f(x) = 5(x^2+8x + 4²) - 4²

f(x) = 5(x+4)² - 16

Learn more on vertex form here: https://brainly.com/question/13912185

Otras preguntas