Answer:
The pair of inequality are 4M +7H < 90 and M + H ≤ 10 ,
Step-by-step explanation:
Consider, the number of short Middle School dances denoted by (M) and the number of longer High School dances denoted by (H)
We have to find the pair of inequalities BEST represents the number of short Middle School dances and the number of longer High School dances that can be performed in the given limitations.
1) Middle School dancers have short programs that run four minutes long and the high School performers will dance with longer programs seven minutes in length.
Also given the entire recital must be over in less than 90 minutes.
Mathematically represented as , 4M +7H < 90.
Also, given that the entire program cannot have more than ten dances.
That is total number of middle school dance and high school dance cannot exceed 10
Mathematically represented as , M + H ≤ 10.
Thus, the pair of inequality are 4M +7H < 90 and M + H ≤ 10.
Answer: M + H ≤ 10 and 4 M + 7 H < 90
Step-by-step explanation:
Here H represents the number of High school dance and M represents the number of middle school dance,
Also, the time take by High school dances = 7 minutes
While, the time taken by middle school dances = 4 minutes
Thus, the total time taken by high school dances = 7 H
And, the time taken by middle school dances = 4 M
According to the question,
The entire program cannot have more than ten dances
That is, M + H ≤ 10
And, the entire recital must be over in less than 90 minutes,
That is, 4 M + 7 H < 90
