Answer:
[tex]\frac{1}{10}[/tex] is the probability of the coin landing on tail and a red marble being drawn.
Step-by-step explanation:
Given A coin is flipped and a random marble is picked from a bag of 10 marbles. Two of the marbles in the bag are red. we have to find the probability of the coin landing on tail and a red marble being drawn.
P(a red marble)=[tex]\frac{No.\thinspaceof\thinspace red\thinspace marbles}{Total\thinspace marbles}[/tex]
=[tex]\frac{2}{10}[/tex]
P(getting a tail)=[tex]\frac{1}{2}[/tex]
Since both events are independent.
∴ P(he coin landing on tail and a red marble being drawn)
=[tex]P(getting\thinspace a\thinspace tail)\times P(a\thinspace red\thinspace marble\thinspace drawn)[/tex]
=[tex]\frac{2}{10}\times \frac{1}{2}[/tex]
= [tex]\frac{1}{10}[/tex]
Hence, [tex]\frac{1}{10}[/tex] is the probability of the coin landing on tail and a red marble being drawn.
