if indeed DEF is a right-triangle, then we can apply the pythagorean theorem and the hypotenuse is really the square root of the sum of the square of the other two, if however the hypotenuse doesn't equal that, then is not,
[tex]\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=\stackrel{hypotenuse}{42}\\ a=\stackrel{adjacent}{26}\\ b=\stackrel{opposite}{23}\\ \end{cases} \\\\\\ 42=\sqrt{26^2+23^2}\implies 42=\sqrt{676+529} \\\\\\ 42=\sqrt{1205}\implies 42\ne 34.7~~\bigotimes[/tex]
Answer:B False
Step-by-step explanation:
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