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The reactant side of a balanced chemical equation is shown below.

Al2(SO4)3 + 3Cl2 →

How many chlorine atoms are there on the product side in the equation?

2
5
6
7

Respuesta :

Matter can be neither created or destroyed so if we 3mol of Cl2 then we have 6 total

So the answer is 6

Answer: Option (c) is the correct answer.

Explanation:

A reaction equation in which there are equal number of reactant and product molecules is known as a balanced equation.

For example, [tex]Al_{2}(SO_{4})_{3} + 3Cl_{2} \rightarrow AlCl_{3} + SO_{4}[/tex]

Number of atoms on reactant side are as follows.

Al = 2

[tex]SO_{4}[/tex] = 3

Cl = 6

Number of atoms on product side are as follows.

Al = 1

[tex]SO_{4}[/tex] = 1

Cl = 3

Therefore, to balance this equation multiply [tex]AlCl_{3}[/tex] by 2 and [tex]SO_{4}[/tex] by 3 on product side.

Hence, the balanced chemical equation is as follows.

   [tex]Al_{2}(SO_{4})_{3} + 3Cl_{2} \rightarrow 2AlCl_{3} + 3SO_{4}[/tex]

Thus, we can conclude that number of total chlorine atoms on product side are 6.