Answer:
Option (D) is correct.
The solution of the quadratic equation [tex]z^2+7z+6=0[/tex] is -6 and -1
Step-by-step explanation:
Consider the given quadratic equation [tex]z^2+7z+6=0[/tex]
We can solve the quadratic equation using middle term splitting method,
7z can be written as z+6z , we get,
[tex]\Rightarrow z^2+7z+6=0[/tex]
[tex]\Rightarrow z^2+z+6z+6=0[/tex]
Taking terms common, we get,
[tex]\Rightarrow z(z+1)+6(z+1)=0[/tex]
Thus, [tex]\Rightarrow (z+6)(z+1)=0[/tex]
Thus, we get (z+6)= 0 or (z+1)= 0
this gives z= -6 or z= -1.
Thus, the solution of the quadratic equation [tex]z^2+7z+6=0[/tex] is -6 and -1
