Answer:
3) 7[tex]\frac{7}{5(n+2)}[/tex]
5) [tex]\frac{9}{k+2}[/tex]
7) [tex]\frac{7b}{b-9}[/tex]
Step-by-step explanation:
3) [tex]\frac{7n+5*7}{5n^{2}+(5*7)n+2*5^{2} }[/tex]
[tex]\frac{7(\frac{7n}{7}+\frac{5*7}{7} ) }{5(\frac{5n^{2} }{5}+\frac{5*7n}{5}+\frac{2*5^{2} }{5} )}[/tex]
5) [tex]\frac{3^{2}(k+5) }{k+2} * \frac{1}{k+5}[/tex]
7)[tex]\frac{5*7*b^{2}+7^{2*b} }{(2*5)b+2*7}[/tex] / [tex]\frac{b-9}{2}[/tex]
[tex]\frac{7b (\frac{5*7b^{2} }{7b} + \frac{7^{2}*b }{7b} )}{2(\frac{2*5b}{2}+\frac{2*7}{2}) }[/tex] / [tex]\frac{b-9}{2}[/tex]
This is my first time using the equation function, hopefully I did it correct.
