ANSWER
The correct answer is D.
[tex] \sum_{n=1} ^{6} (n - 3) = ( - 2) + ( - 1) + (0) + (1) + (2) + (3) = 3[/tex]
EXPLANATION
The given expression is
[tex] \sum_{n=1} ^{6} (n - 3)[/tex]
The symbol means summation.
So we need to substitute
[tex]n=1,n=2,n=3,n=4,n=5, \:and\:n=6[/tex]
into the formula and add all to get,
[tex] \sum_{n=1} ^{6} (n - 3) = (1 - 3) + (2 - 3) + (3- 3) + (4 - 3) + (5 - 3) + (6 - 3)[/tex]
We simplify to obtain,
[tex] \sum_{n=1} ^{6} (n - 3) = ( - 2) + ( - 1) + (0) + (1) + (2) + (3) = 3[/tex]
The correct answer is D
