Complete the paragraph to describe the characteristics of a silicon tetrahydride molecule (SiH4). The Lewis structure and table of electronegativities are given.

The bonds present in SiH4 are polar due to difference in electronegativity between Silicon and hydrogen
The molecular shape is tetrahedral
the hybridization is sp3
In spite of the polarity of bonds of SiH4, the molecule is non polar due to overall zero dipole moment in the molecule.
The dipole moment is the product of charge and distance between charged particles. It is a vector quantity and thus it is directional
All the four bonds of Si-H are polar however the dipoles of each bond cancel each other and the net dipole is zero
hence the molecule is non polar
So answers are
a) Polar
b) tetrahedral
c) non polar
Answer: The correct answer is polar, tetrahedral and non-polar.
Explanation:
It is given a compound which is silicon tetrahydride having formula [tex]SiH_4[/tex]
The electronegativities of silicon and hydrogen are 1.9 and 2.1 respectively.
Difference in electronegativity = 2.1 - 1.9 = 0.2
From above, some difference in the electronegativities of the atoms is there. This means that bond polarity of this molecule is polar. If the difference would have been 0, the bond polarity of the molecule is taken as non-polar.
[tex]\text{Number of electrons}=\frac{1}{2}[V+N-C+A][/tex]
where,
V = number of valence electrons present in central atom i.e. Silicon = 4
N = number of monovalent atoms bonded to central atom = 4
C = charge of cation = 0
A = charge of anion = 0
Putting values in above equation, we get:
[tex]\text{Number of electron pairs} =\frac{1}{2}[4+4-0+0]=4[/tex]
As, the total number of electron pairs is 4, this means that the hybridization of this molecule will be [tex]sp^3[/tex] and the molecular shape will be tetrahedral.
Hence, the correct answer is polar, tetrahedral and non-polar.