Answer: 4.74 moles
Explanation:
[tex]2LiBr+Ba\rightarrow BaBr_2+2Li[/tex]
Moles of Ba=[tex]\frac{\text {given mass}}{\text {molar mass}}[/tex]
Moles of Ba=[tex]\frac{325g}{137g/mol}=2.37 moles[/tex]
According to given balanced equation,
1 mole of Barium gives 2 moles of Li
Thus 2.37 moles of Barium gives=[tex]\frac{2}{1}\times 2.37=4.74 moles[/tex]
Thus 4.74 moles of lithium will be produced by 135 g of barium.
