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Answer:
The probability of getting a factor of 12 on a fair dice is 5/6 or approximately 83%.
Step-by-step explanation:
Probability is expressed as a fraction where the denominator is the total number of outcomes and the numerator is the number of desired outcomes. In this case, the desired outcome is any factor of 12. The factors of 12 are the numbers we multiply together to get that number: 1, 2, 3, 4, 6 and 12. Since a fair dice has the total outcomes of either 1, 2, 3, 4, 5 or 6, then the total outcomes is 6 and the possibility that we could roll the desired outcome (factor of 12) is 5, the probability is 5 out of 6 or 5/6, which when divided is approximately 83%.
The probability of getting a factor of 12 is [tex]\dfrac{5}{6}[/tex].
Probability
The probability helps us to know the chances of an event occurring.
[tex]\rm{Probability=\dfrac{Desired\ Outcomes}{Total\ Number\ of\ outcomes\ possible}[/tex]
To find
the probability of getting a factor of 12.
Solution
Factors of 12
Factors of 12 = {1, 2, 3, 4, 6, 12}
Possible outcomes on Dice
As we can see on the dice, only numbers less than or equal to 6, can occur, so, the numbers possible are 1, 2, 3, 4, and 6.
Therefore, the total number of possible outcomes is 5.
We know that on a dice there are only 6 possible outcomes.
Probability of getting a factor of 12
Probability of getting a factor of 12
[tex]\rm{Probability\ of\ getting\ a\ factor\ of\ 12 = \dfrac{possibel\ factors\ of\ 12}{All\ possible outcomes\ on\ the\ dice}[/tex]
[tex]=\dfrac{5}{6}[/tex]
Hence, the probability of getting a factor of 12 is [tex]\dfrac{5}{6}[/tex].
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