Respuesta :

altavistard

Answer:


Step-by-step explanation:

Let's analyze y = 3x - 1.  This is the equation of a straight line in slope-intercept form; the slope, m, is 3, and the y-intercept, b, is -1.

Unfortunately, even when I magnify the given graphs, I cannot see enough detail to warrant choosing one of these graphs over the other three.

Omit the 1st and 4th graphs; they're just not detailed enough.  the 2nd and 3rd graphs look just about identical to me.  Find the point (0, -1) on each and also find the point (5, [3(5) - 1]), or (5, 14) on both.  Then try to decide which graph seems to pass through these two points most closely.


MrRoyal

The graph of a linear function is represented by a straight line.

None of the graphs represent [tex]\mathbf{y = 3x - 1}[/tex]

The equation is given as:

[tex]\mathbf{y = 3x - 1}[/tex]

A linear function is represented as:

[tex]\mathbf{y = mx + c}[/tex]

Where:

[tex]\mathbf{m = 3}[/tex] --- the slope

[tex]\mathbf{c = -1}[/tex] -- the y-intercept

Because [tex]\mathbf{y = 3x - 1}[/tex] has a y-intercept other than 0.

Then, it means that the graph o [tex]\mathbf{y = 3x - 1}[/tex] does not pass through the origin (0,0)

All the graphs in the option pass through (0,0)

Hence, none of the graphs represent [tex]\mathbf{y = 3x - 1}[/tex]

Read more about linear graphs at:

https://brainly.com/question/20853486

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