Answer: The kinetic energy of an apple at 100 m of height while falling is 49 J.
Explanation:
Mass of the apple = 0.100 kg
Height at that instant when apple was at verge of falling = 150 m
The sum of the potential energy and kinetic remains constant.
Sum of P.E and K.E energy at height if 150 m
[tex]P.E+K.E=mgh+\frac{1}{2}mv^2[/tex]
Kinetic energy is zero at initial position
[tex]=0.100 kg\times 9.8 m/s^2\times 150 m=147 J+0 J=147 J[/tex]
Sum of P.E and K.E at height if 100 m
[tex]P.E+K.E=mgh'+\frac{1}{2}mv^2[/tex]
Kinetic energy is not zero during falling of an apple
[tex]=0.100 kg\times 9.8 m/s^2\times 100 m=98 J+K.E.=147 J[/tex]
K.E = 147 J - 98 J= 49 J
The kinetic energy of an apple at 100 m of height while falling is 49 J.
