Answer:
Option (1) is correct.
The product of [tex](y+3)(y^2-3y+9)[/tex] is [tex]y^3+27[/tex]
Step-by-step explanation:
Given, [tex](y+3)(y^2-3y+9)[/tex]
We have to find the product of above,
We have to multiply each term as ,
[tex](y+3)(y^2-3y+9)[/tex] can be written as,
[tex]\Rightarrow y(y^2-3y+9)+3(y^2-3y+9)[/tex]
When we multiply each term we get,
[tex]\Rightarrow (y^3-3y^2+9y)+(3y^2-9y+27)[/tex]
These terms are same as we have filled in table below.
On adding like terms we get,
[tex]\Rightarrow y^3-3y^2+9y+3y^2-9y+27[/tex]
[tex]\Rightarrow y^3+27[/tex]
Thus, the product of [tex](y-3)(y^2-3y+9)[/tex] is [tex]y^3+27[/tex]
