Answer: 50 %
Step-by-step explanation:
From the given table the number of 11th students = n(11th)=30
The number of science students n(S)= 6+7+5+7=25
The number of students in 11th and science= n(11th ∩ S)=5
Now, the number of students in 11th grade or selected Science
n(11th ∪ S)=n(11th)+n(S)-n(11th∩S)
⇒n(11th ∪ S)=30+25-5=60
Now, The percent chance there is that a student selected at random is in 11th grade or selected Science as their favorite subject
[tex]=\frac{n(11th\ \cup S )}{120}\times100=\frac{60}{120}\times100=50\%[/tex]
