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The charge on the plates of a parallel plate capacitor determines which of the following? Select all that apply. The electric field across the plates. The potential across the plates. The capacitance of the capacitor. The current in the circuit. The resistance of the circuit.

Respuesta :

Electric field between the plates of capacitor is given by

[tex]E = \frac{Q}{A\epsilon_0}[/tex]

potential difference between the plates of capacitor is given by

[tex]V = E.d[/tex]

[tex]V = \frac{Qd}{A\epsilon_0}[/tex]

so above two parameters will depend on the charge of capacitor

rest we know that capacitance of capacitor is given as

[tex]C = \frac{\epsilon_0 A}{d}[/tex]

so it is independent of charge

so correct answer will be

The electric field across the plates.

The potential across the plates.

Answer:

The electric field across the plates.

The potential across the plates.

Explanation:

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