Answer:
see explanation
Step-by-step explanation:
given a parabola in standard form : y = ax² + bx + c : a ≠ 0
Then the x- coordinate of the vertex which is also the axis of symmetry is
[tex]x_{vertex}[/tex] = - [tex]\frac{b}{2a}[/tex]
y = 3x² - 24x + 38 is in standard form
with a = 3, b = - 24 and c = 38, hence
[tex]x_{vertex}[/tex] = - [tex]\frac{-24}{6}[/tex] = 4
Substitute x = 4 into the equation for corresponding y- coordinate
y = 3(4)² - 24(4) + 38 = 48 - 96 + 38 = - 10
vertex = (4, - 10)
equation of axis of symmetry is x = 4
