Answer: The total force in the bottom of the swimming pool is 196,000 kilo-Newtons.
Explanation:
The force on the bottom of the swimming pool =F
[tex]Force=Pressure\times Area[/tex]
Density of the water = [tex]\rho =1000 kg/m^3[/tex]
Pressure at the bottom of the swimming pool=[tex]\rho gh=1000 kg/m^3\times 9.8 m/s^2\times 4m[/tex]=39,200 Pascal[/tex]
Area at the bottom of the swimming pool :
Length of the base = 100 m
Width of the base = 50 m
= [tex]100 m\times 50 m=5000 m^2[/tex]
[tex]Force=Pressure\times Area=39,200 Pascal\times 5000 m^2=196,000,000 N=196,000 kilo-Newtons[/tex]
The total force in the bottom of the swimming pool is 196,000 kilo-Newtons.
