Answer : Weight of the truck = 9408 N
Explanation :
Given that,
Length = 6.0 m
Width = 4.0 m
Depth = 4.00 cm
we know that,
weight of the truck = weight of the displaced water
weight of the truck = [tex]m_{water}\times g[/tex]
we know that,
density [tex]\rho = \dfrac{mass}{volume}[/tex]
mass = density X volume
weight of the truck = [tex]\rho_{w}\times V_{w}\times g[/tex]
Now, the volume = length X width X depth
[tex]V = 6.0\ m\times 4.0\ m \times 0.04\ m[/tex]
[tex]V = 0.96\ m^{3}[/tex]
Weight of the truck [tex]= 1000\ kg/m^{3}\times 0.96\ m^{3}\times 9.8\ m/s^{2}[/tex]
Weight of the truck = [tex]= 9408\ kg- m/s^{2}[/tex]
Weight of the truck = 9408 N
Hence, this is the required solution.
