1. You are making gift bags to give to your friends at a birthday party. You have 36 candy bars, 24 pencils, and 48 erasers to divide among the gift bags. You want to divide the items evenly and not have any items left over. a. List the common factors of 36, 24, and 48. Which common factor represents the greatest number of gift bags you can make? Explain. b. If you make the greatest number of gift bags, how many of each item would go in each bag? Show how you know.

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Answer: 12

A. The common factors of 36, 24, and 48 is that they are all factors of the number 12.

B. If making the greatest number of gift bags without having anything left over and so that each item is distributed evenly between all of the bags, you would have to find the highest common denominator for those numbers and that number is 12.

The number of items in each bag would be:

Candy Bars - 36 / 12 Bags = 3 per bag.
Pencils - 24 / 12 Bags = 2 per bag.
Erasers - 48 / 12 Bags = 4 per bag.

The maximum number of bags that can be made is 12, and each of the 12 bags will have 2 pencils, 3 candy bars and 4 erasers.

Since you are making gift bags to give to your friends at a birthday party, and you have 36 candy bars, 24 pencils, and 48 erasers to divide among the gift bags, and you want to divide the items evenly and not have any items left over, to determine, if you make the greatest number of gift bags, how many of each item would go in each bag, the following calculation must be performed:

The common major divisor of the 3 numbers must be obtained.

  • 24 = 2, 3, 4, 6, 8, 12, 24
  • 36 = 2, 3, 4, 6, 9, 12, 18, 36
  • 48 = 2, 3, 4, 6, 8, 12, 24, 48

Therefore, the greatest common divisor of these numbers is 12, with which the maximum number of bags that can be made is 12.

Thus, in each of the 12 bags there will be 2 pencils, 3 candy bars and 4 erasers.

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