Respuesta :

gmany

[tex]P_1(x_1;\ y_1);\ P_2(x_2;\ y_2)\\\\|P_1P_2|=d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}[/tex]

Answer:

[tex]\left|P_1P_2\right|=d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Step-by-step explanation:

Let the coordinates of the given point are as follows,

[tex]P_1=(x_1,y_1)\:\:and\:\:P_2=(x_2,y_2)[/tex]

Now The distance between point [tex]P_1\:\:andP_2[/tex] is given by,

[tex]\left|P_1P_2\right|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Therefore,  [tex]\left|P_1P_2\right|=d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]