A car accelerates uniformly from rest to a speed of 6.6 m/s in 6.5 s. How far does the car travel in that time? (Show all work)

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rokettojanpu rokettojanpu · Answer 1 · 2019-01-24T22:20:04+01:00

You can find this kinematics equation in any old high school physics textbook:

d = [tex]\frac{Vi+Vf}{2}[/tex]×Δt

d is the distance traveled.

Vi is the initial velocity.

Vf is the final velocity.

Δt is the amount of elapsed time.

Given values:

Vi = 0 m/s

Vf = 6.6 m/s

Δt = 6.5 s

Substitute the terms in the equation with your given values and solve for d:

d = [tex]\frac{0+6.6}{2}[/tex]×6.5

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asuwafohjames asuwafohjames · Answer 2 · 2021-09-09T15:01:34+02:00

The car will travel for 21.45 m

How far is another word for total distance covered

Applying the equation of motion,

s = (v+u)t/2................. Equation 1

Where, s = distance covered by the car, v = final velocity of the car, u = initial velocity, t = time

From the question,

Given: v = 6.6 m/s, u = 0 m/s (from rest), t = 6.5 s

Substitute these values into equation 1

s = (6.6+0)6.5/2

s = 21.45 m

Hence the car travels for 21.45 m

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